The following equation is almost true.
And by almost true, I mean correct to well over 200 decimal places. This sum comes from [1]. Here I will show why the two sides are very nearly equal and why they’re not exactly equal.
Let’s explore the numerator of the sum with a little code.
>>> from math import tanh, pi >>> for n in range(1, 11): print(n*tanh(pi)) 0.99627207622075 1.9925441524415 2.98881622866225 3.985088304883 .... 10.95899283842825
When we take the floor (the integer part [2]) of the numbers above, the pattern seems to be
⌊n tanh π⌋ = n − 1
If the pattern continues, our sum would be 1/81. To see this, multiply the series by 100, evaluate the equation below at x = 1/10, and divide by 100.
Our sum is close to 1/81, but not exactly equal to it, because
⌊n tanh π⌋ = n − 1
holds for a lot of n‘s but not for all n.
Note that
tanh π = 0.996… = 1 − 0.00372…
and so
⌊n tanh π⌋ = n − 1
will hold as long as n < 1/0.00372… = 268.2…
Now
⌊268 tanh π⌋ = 268 − 1
but
⌊269 tanh π⌋ = 269 −2.
So the 269th term on the left side
is less than the 269th term of the sum
10−2 + 2×10−3 + 3×10−4 + … = 1/81
for the right side.
We can compare the decimal expansions of both sides by using the Mathematica command
N[Sum[Floor[n Tanh[Pi]]/10^n, {n, 1, 300}], 300]
This shows the following:
Related posts
[1] J. M. Borwein and P. B. Borwein. Strange Series and High Precision Fraud. The American Mathematical Monthly, Vol. 99, No. 7, pp. 622-640
[2] The floor of a real number x is the greatest integer ≤ x. For positive x, this is the integer part of x, but not for negative x.
You may find redpenblack’s video proving the sum converges to 1/81 worth sharing.
https://youtu.be/opeW_1aG2sU