By the nth day of Christmas, my true love had sent to me n(n+1)(n+2)/6 gifts.
Explanation and proof here.
3 thoughts on “By the nth day of Christmas”
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By the nth day of Christmas, my true love had sent to me n(n+1)(n+2)/6 gifts.
Explanation and proof here.
Comments are closed.
2nd day, 2 + 1 = 3 != 2 x 3 x 4 / 6
3rd day, 3 + 2 + 1 = 6 != 3 x 4 x 5 / 6
Scott:
On the nth day, there are n + (n-1) + … + 2 + 1 = n(n+1)/2 new gifts, and a cumulative total of n(n+1)(n+2)/6 gifts.
2nd day, (2 + 1) + 1 = 4 = 2*3*4/6
3rd day, (3+ 2 + 1) + (2 + 1) + 1 = 10 = 3*4*5/6
Does a Partridge and a Pair Tree count as two gifts, or as one?